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This titration calculator is used to determine the unknown molarity (concentration) of an acid or base solution from titration data. Also, it allows us to determine the volumes of the titrants and the moles of H+ and OH- involved in the chemical reaction. By calculating these values, it is easy to understand how strong or weak an acid or base is in a solution.
"The process of chemical analysis in which a solution of known concentration (titrant) is slowly added to a solution of unknown concentration (analyte) until the reaction reaches a neutral point."
The known volume of titrant is added until a solution reaches a pH ratio of 1:1. When a base or acid is dissolved in water, its H⁺ or OH- ions will dissociate, which will change the natural self-ionization balance of water:
2H₂O ⇌ OH⁻ + H₃O⁺
It will become a stronger acid-base titration solution. At pH 7, the concentrations of H₃O⁺ and OH⁻ are 1:1 (the titration equivalence point).
This titration formula determines the unknown concentration of a solution (analyte) reacting with a solution of known concentration (titrant).
nH+ . Va . Ma = nOH- . Mb. Vb
Where:
Preparation:
Titration:
Endpoint:
Note the initial volume of the titrant in the burette and the volume of the analyte from the flask.
Add the titrant to the analyte until the indicator shows a certain change in color, and then record the final volume
Calculate the volume of the titrant by using the formula below:
Volume of titrant used = Final volume − Initial volume
Using the titration formula, the unknown concentration (molarity) is calculated. Look at the example below, which uses the same process step by step.
The method is a valuable addition when your experiment involves manual determination. To automate the process, you can use the online titration calculator.
Find the concentration of acetic acid in vinegar when the NaOH solution is 0.100 M. We used 25.00 mL of the NaOH solution to titrate the vinegar solution to the equivalence point.
CH3COOH + NaOH → CH3COONa (aq) + H2O
Solution:
Calculate the millimoles (mmol) of NaOH used:
mmol NaOH = Moles of NaOH * Volume of NaOH
= 0.100 M * 25.00 mL
= 2.50 mmol
Since the reaction between acetic acid and NaOH is 1:1, the millimoles of acetic acid used equal the millimoles of NaOH used.
mmol of CH3COOH = 2.50 mmol
Step 3: Calculate the molarity of acetic acid
Molarity = mmol of solute ÷ volume of solution
Molarity of CH₃COOH = 2.50 mmol ÷ 10.00 mL
Molarity of CH₃COOH = 0.250 M
Therefore, the concentration of acetic acid in the vinegar solution is 0.250 M.
The pH of the solution at the equivalence point depends on the relative concentrations of the acid and base. You can estimate the pH value of the equivalence point according to the following rule:
If the base is stronger than the acid, the solution will be alkaline, and if the acid is stronger than the base, the solution will be acidic. If the weak acid and weak base have equal strengths and concentrations, the resulting solution will be neutral, with a pH of 7. Therefore, it is difficult to titrate with a weak acid or base because there is no color change.
| Formula | Name | Strength |
| NaOH | Sodium hydroxide | Strong |
| KOH | Potassium hydroxide | Strong |
| Ca(OH)2 | Calcium hydroxide | Strong |
| Ba(OH)2 | Barium hydroxide | Strong |
| NH3 | Ammonia | Weak |
| CH3NH2 | Methylamine | Weak |
| C5H5N | Pyridine | Weak |
| Formula | Name | Strength |
| HCl | Hydrochloric acid | Strong |
| HNO3 | Nitric acid | Strong |
| H2SO4 | Sulfuric acid | Strong |
| HBr | Hydrobromic acid | Strong |
| HI | Hydroiodic acid | Strong |
| HClO4 | Perchloric acid | Strong |
| HClO3 | Chloric acid | Strong |
| HCOOH | Formic acid | Weak |
| CH3COOH | Acetic acid | Weak |
| C6H5COOH | Benzoic acid | Weak |
| HF | Hydrofluoric acid | Weak |
| HNO2 | Nitrous acid | Weak |
| H3PO4 | Phosphoric acid | Weak |
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